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## What is the probability of getting a total of 15 when three dice are thrown?

If three dices are thrown simultaneously, then the number of all the possible outcomes are 6^{3} = **216**. Let A be the event of getting a sum of 15 when three dices are thrown simultaneously.

## How many ways can a sum of 15 be obtained when rolling 3 dice?

There are **three ways** to roll 15 with three dice: 663, 654 and 555.

## What is the probability of 3 dice?

Two (6-sided) dice roll probability table

Roll a… | Probability |
---|---|

3 | 3/36 (8.333%) |

4 | 6/36 (16.667%) |

5 | 10/36 (27.778%) |

6 | 15/36 (41.667%) |

## What is the probability of getting a sum has 3 If a dice is thrown?

We know that the number of possible outcomes is 36. Thus, the probability of getting multiples of 3 as a sum of digits on dice is =**1236=13**. Note: We must calculate the number of favourable and possible outcomes in each case to calculate the probability of each of the given events.

## When three dice are thrown simultaneously then total number of outcomes are?

Solution: Three different dice are thrown at the same time. Therefore, total number of possible outcomes will be 6^{3} = (6 × 6 × 6) = **216**.

## What is the probability of rolling a sum of 3?

We divide the total number of ways to obtain each sum by the total number of outcomes in the sample space, or 216. The results are: Probability of a sum of **3: 1/216 = 0.5%** Probability of a sum of 4: 3/216 = 1.4%

## What is the formula of probability?

P(**A**) is the probability of an event “A” n(A) is the number of favourable outcomes. n(S) is the total number of events in the sample space.

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Basic Probability Formulas.

All Probability Formulas List in Maths | |
---|---|

Conditional Probability | P(A | B) = P(A∩B) / P(B) |

Bayes Formula | P(A | B) = P(B | A) ⋅ P(A) / P(B) |